Integrand size = 11, antiderivative size = 83 \[ \int x^3 (a+b x)^n \, dx=-\frac {a^3 (a+b x)^{1+n}}{b^4 (1+n)}+\frac {3 a^2 (a+b x)^{2+n}}{b^4 (2+n)}-\frac {3 a (a+b x)^{3+n}}{b^4 (3+n)}+\frac {(a+b x)^{4+n}}{b^4 (4+n)} \]
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Time = 0.03 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {45} \[ \int x^3 (a+b x)^n \, dx=-\frac {a^3 (a+b x)^{n+1}}{b^4 (n+1)}+\frac {3 a^2 (a+b x)^{n+2}}{b^4 (n+2)}-\frac {3 a (a+b x)^{n+3}}{b^4 (n+3)}+\frac {(a+b x)^{n+4}}{b^4 (n+4)} \]
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Rule 45
Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {a^3 (a+b x)^n}{b^3}+\frac {3 a^2 (a+b x)^{1+n}}{b^3}-\frac {3 a (a+b x)^{2+n}}{b^3}+\frac {(a+b x)^{3+n}}{b^3}\right ) \, dx \\ & = -\frac {a^3 (a+b x)^{1+n}}{b^4 (1+n)}+\frac {3 a^2 (a+b x)^{2+n}}{b^4 (2+n)}-\frac {3 a (a+b x)^{3+n}}{b^4 (3+n)}+\frac {(a+b x)^{4+n}}{b^4 (4+n)} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.81 \[ \int x^3 (a+b x)^n \, dx=\frac {(a+b x)^{1+n} \left (-\frac {a^3}{1+n}+\frac {3 a^2 (a+b x)}{2+n}-\frac {3 a (a+b x)^2}{3+n}+\frac {(a+b x)^3}{4+n}\right )}{b^4} \]
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Time = 0.13 (sec) , antiderivative size = 126, normalized size of antiderivative = 1.52
method | result | size |
gosper | \(-\frac {\left (b x +a \right )^{1+n} \left (-b^{3} n^{3} x^{3}-6 b^{3} n^{2} x^{3}+3 a \,b^{2} n^{2} x^{2}-11 b^{3} n \,x^{3}+9 a \,b^{2} n \,x^{2}-6 b^{3} x^{3}-6 a^{2} b n x +6 a \,b^{2} x^{2}-6 a^{2} b x +6 a^{3}\right )}{b^{4} \left (n^{4}+10 n^{3}+35 n^{2}+50 n +24\right )}\) | \(126\) |
risch | \(-\frac {\left (-b^{4} n^{3} x^{4}-a \,b^{3} n^{3} x^{3}-6 b^{4} n^{2} x^{4}-3 a \,b^{3} n^{2} x^{3}-11 b^{4} n \,x^{4}+3 a^{2} b^{2} n^{2} x^{2}-2 x^{3} a n \,b^{3}-6 b^{4} x^{4}+3 a^{2} n \,x^{2} b^{2}-6 x n \,a^{3} b +6 a^{4}\right ) \left (b x +a \right )^{n}}{\left (3+n \right ) \left (4+n \right ) \left (2+n \right ) \left (1+n \right ) b^{4}}\) | \(146\) |
norman | \(\frac {x^{4} {\mathrm e}^{n \ln \left (b x +a \right )}}{4+n}+\frac {a n \,x^{3} {\mathrm e}^{n \ln \left (b x +a \right )}}{b \left (n^{2}+7 n +12\right )}-\frac {6 a^{4} {\mathrm e}^{n \ln \left (b x +a \right )}}{b^{4} \left (n^{4}+10 n^{3}+35 n^{2}+50 n +24\right )}-\frac {3 a^{2} n \,x^{2} {\mathrm e}^{n \ln \left (b x +a \right )}}{b^{2} \left (n^{3}+9 n^{2}+26 n +24\right )}+\frac {6 n \,a^{3} x \,{\mathrm e}^{n \ln \left (b x +a \right )}}{b^{3} \left (n^{4}+10 n^{3}+35 n^{2}+50 n +24\right )}\) | \(160\) |
parallelrisch | \(\frac {x^{4} \left (b x +a \right )^{n} b^{4} n^{3}+6 x^{4} \left (b x +a \right )^{n} b^{4} n^{2}+x^{3} \left (b x +a \right )^{n} a \,b^{3} n^{3}+11 x^{4} \left (b x +a \right )^{n} b^{4} n +3 x^{3} \left (b x +a \right )^{n} a \,b^{3} n^{2}+6 x^{4} \left (b x +a \right )^{n} b^{4}+2 x^{3} \left (b x +a \right )^{n} a \,b^{3} n -3 x^{2} \left (b x +a \right )^{n} a^{2} b^{2} n^{2}-3 x^{2} \left (b x +a \right )^{n} a^{2} b^{2} n +6 x \left (b x +a \right )^{n} a^{3} b n -6 \left (b x +a \right )^{n} a^{4}}{b^{4} \left (n^{4}+10 n^{3}+35 n^{2}+50 n +24\right )}\) | \(213\) |
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Time = 0.24 (sec) , antiderivative size = 143, normalized size of antiderivative = 1.72 \[ \int x^3 (a+b x)^n \, dx=\frac {{\left (6 \, a^{3} b n x + {\left (b^{4} n^{3} + 6 \, b^{4} n^{2} + 11 \, b^{4} n + 6 \, b^{4}\right )} x^{4} - 6 \, a^{4} + {\left (a b^{3} n^{3} + 3 \, a b^{3} n^{2} + 2 \, a b^{3} n\right )} x^{3} - 3 \, {\left (a^{2} b^{2} n^{2} + a^{2} b^{2} n\right )} x^{2}\right )} {\left (b x + a\right )}^{n}}{b^{4} n^{4} + 10 \, b^{4} n^{3} + 35 \, b^{4} n^{2} + 50 \, b^{4} n + 24 \, b^{4}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 1318 vs. \(2 (71) = 142\).
Time = 1.84 (sec) , antiderivative size = 1318, normalized size of antiderivative = 15.88 \[ \int x^3 (a+b x)^n \, dx=\text {Too large to display} \]
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Time = 0.20 (sec) , antiderivative size = 101, normalized size of antiderivative = 1.22 \[ \int x^3 (a+b x)^n \, dx=\frac {{\left ({\left (n^{3} + 6 \, n^{2} + 11 \, n + 6\right )} b^{4} x^{4} + {\left (n^{3} + 3 \, n^{2} + 2 \, n\right )} a b^{3} x^{3} - 3 \, {\left (n^{2} + n\right )} a^{2} b^{2} x^{2} + 6 \, a^{3} b n x - 6 \, a^{4}\right )} {\left (b x + a\right )}^{n}}{{\left (n^{4} + 10 \, n^{3} + 35 \, n^{2} + 50 \, n + 24\right )} b^{4}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 226 vs. \(2 (83) = 166\).
Time = 0.29 (sec) , antiderivative size = 226, normalized size of antiderivative = 2.72 \[ \int x^3 (a+b x)^n \, dx=\frac {{\left (b x + a\right )}^{n} b^{4} n^{3} x^{4} + {\left (b x + a\right )}^{n} a b^{3} n^{3} x^{3} + 6 \, {\left (b x + a\right )}^{n} b^{4} n^{2} x^{4} + 3 \, {\left (b x + a\right )}^{n} a b^{3} n^{2} x^{3} + 11 \, {\left (b x + a\right )}^{n} b^{4} n x^{4} - 3 \, {\left (b x + a\right )}^{n} a^{2} b^{2} n^{2} x^{2} + 2 \, {\left (b x + a\right )}^{n} a b^{3} n x^{3} + 6 \, {\left (b x + a\right )}^{n} b^{4} x^{4} - 3 \, {\left (b x + a\right )}^{n} a^{2} b^{2} n x^{2} + 6 \, {\left (b x + a\right )}^{n} a^{3} b n x - 6 \, {\left (b x + a\right )}^{n} a^{4}}{b^{4} n^{4} + 10 \, b^{4} n^{3} + 35 \, b^{4} n^{2} + 50 \, b^{4} n + 24 \, b^{4}} \]
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Time = 0.59 (sec) , antiderivative size = 176, normalized size of antiderivative = 2.12 \[ \int x^3 (a+b x)^n \, dx={\left (a+b\,x\right )}^n\,\left (\frac {x^4\,\left (n^3+6\,n^2+11\,n+6\right )}{n^4+10\,n^3+35\,n^2+50\,n+24}-\frac {6\,a^4}{b^4\,\left (n^4+10\,n^3+35\,n^2+50\,n+24\right )}+\frac {6\,a^3\,n\,x}{b^3\,\left (n^4+10\,n^3+35\,n^2+50\,n+24\right )}+\frac {a\,n\,x^3\,\left (n^2+3\,n+2\right )}{b\,\left (n^4+10\,n^3+35\,n^2+50\,n+24\right )}-\frac {3\,a^2\,n\,x^2\,\left (n+1\right )}{b^2\,\left (n^4+10\,n^3+35\,n^2+50\,n+24\right )}\right ) \]
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